a worker pushes a 1420 N crate with a horizontal force of 420 N a distance of 27m. assume the coefficient between the crate and the floor is 0.22. what is the net force done on the crate?
Net Force = Fap - Fk = 420-0.22*1420 =
107.6 N.
To find the net force on the crate, we need to consider the frictional force acting on the crate as well. The formula to calculate the frictional force is:
Frictional force = coefficient of friction * normal force
In this case, the normal force is equal to the weight of the crate, since it is on a horizontal surface and not accelerating vertically. The weight of the crate (mg) can be calculated using the formula:
Weight = mass * acceleration due to gravity
Given that the weight of the crate is 1420 N, we can divide it by the acceleration due to gravity (9.8 m/s^2) to find the mass of the crate:
Mass = Weight / acceleration due to gravity
So, Mass = 1420 N / 9.8 m/s^2
Once we have the mass of the crate, we can calculate the normal force by multiplying it with the acceleration due to gravity:
Normal force = Mass * acceleration due to gravity
To find the frictional force exerted on the crate, we multiply the normal force by the coefficient of friction:
Frictional force = coefficient of friction * normal force
Now, to calculate the net force on the crate, we need to consider the worker's applied force. Since the worker is pushing the crate horizontally, the force applied by the worker is equal to the horizontal force:
Applied force = 420 N
Finally, the net force can be calculated by subtracting the frictional force from the applied force:
Net force = Applied force - Frictional force
Plug in the values we obtained to find the net force on the crate.