An isosceles right triangle has an area of 98cm squared. Find the length of each leg.

The formula of finding the area of a triangle with one right angle is:

(b x h)/2

You know that an isoceles triangles has two equal sides. Those equal sides are the base and height. This means that both the base height with have the same value.

After you get the answer of the two isoceles legs, you need to figure out the other leg. To solve this by using the formula:

a^2+b^2=c^2

a would be on leg length
b would be the other leg length

You just fill in the values and you get your answer. =)

this did not help

If the area is 98 then the sides would be equal to b x h / 2. So they would be

98=b x h /2
98 x 2= b x h
196= b x h (we know that the base and the height are the same so you can just find the square root of 196)

square root of 196= 14x14

So the two sides are 14 and 14

Now we need to find the third side.

We will use the formula:

a^2+b^2=c^2

14^2+14^2=c^2
196+196=c^2
329=c^2

So the side lengths of the triangle are

(14,14, square root of 329)

f

14 by 14 by 18.14

Thx for the help this really helped me.

Why don't triangles ever tell secrets?

Because they're all right angles!

To find the length of each leg of an isosceles right triangle with an area of 98 cm squared, you can follow these steps:

Step 1: Use the formula for the area of a triangle with one right angle, which is (base × height)/2. Since the triangle is isosceles, both the base and height will have the same value.

Let's denote the length of the base and height as "x".
Therefore, the area of the triangle can be represented as (x × x)/2 = 98.

Step 2: Solve for x by multiplying both sides of the equation by 2 and rearranging the equation:

2 * (x × x)/2 = 2 * 98
x × x = 196

Step 3: Take the square root of both sides of the equation to solve for x:

√(x × x) = √196
x = √196

Step 4: Simplify the square root of 196 to find the length of each leg:

x = 14

So, each leg of the isosceles right triangle has a length of 14 cm.

To find the length of each leg of an isosceles right triangle with an area of 98cm squared, you can start by using the formula for the area of a triangle with one right angle: (b x h)/2, where b is the base and h is the height.

Since the triangle is isosceles, both the base and height have the same value. Let's call this value x. So the formula becomes: (x x x)/2 = 98.

Simplifying this equation, we have: (x^2)/2 = 98.

To solve for x, we can multiply both sides of the equation by 2, giving us: x^2 = 196.

Taking the square root of both sides, we find: x = √196, which is equal to 14.

So each leg of the isosceles right triangle is 14 cm.

Now, let's find the length of the other leg using the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (c) is equal to the sum of the squares of the other two sides (a and b): a^2 + b^2 = c^2.

Since both legs of the triangle are the same length (14 cm), we can substitute 14 for both a and b in the equation: 14^2 + 14^2 = c^2.

Simplifying, we get: 196 + 196 = c^2.

Which further simplifies to: 392 = c^2.

To find the length of the hypotenuse (c), we take the square root of both sides: √392 = c.

The square root of 392 is approximately 19.8.

So the length of each leg of the isosceles right triangle is 14 cm, and the length of the hypotenuse is approximately 19.8 cm.