I just can't do this...
Two moles of potassium chloride and three moles of oxygen are produced from the decomposition of two moles of potassium chorate. What is the balanced equation? How many moles of oxygen are produced from twelve moles of postassium chlorate?
potassium chlorate is KClO3
oxygen is O2
potassium chloride is KCl
The problem tells you that equation AND it tells you the coefficients.
2KClO3 ==> 2KCl + 3O2
Look at the equation. If 2 mols KClO3 will formm 3 mols O2, how much O2 will we have from 4 mols KClO3? 6mols KClO3? 12 mols KClO3?
Thanks I got it now.
so in order to find out how many moles of O2 are produced from 12 moles of KClO3:
2 mols KClO3 form 3 mols O2
4 mols KClO3 form ? mols O2
Do you double the mols of O2
4 mols KClO3 form 6 mols O2?
6 mols KClO3 form 9 mols O2?
18 mols of oxygen
To find out how many moles of oxygen (O2) are produced from 12 moles of potassium chlorate (KClO3), you can use the ratio from the balanced equation:
2 moles KClO3 --> 3 moles O2
First, determine the ratio of moles of KClO3 to moles of O2. For every 2 moles of KClO3, there are 3 moles of O2. Therefore, the ratio is 3 moles O2 per 2 moles KClO3.
To calculate the moles of O2 produced from 12 moles of KClO3, you can set up a proportion:
(3 moles O2 / 2 moles KClO3) = (x moles O2 / 12 moles KClO3)
Simplifying the proportion gives:
3/2 = x/12
Now, cross-multiply and solve for x:
2x = 36
Divide both sides by 2:
x = 18
Therefore, from 12 moles of KClO3, you will produce 18 moles of O2.
To find out how many moles of O2 are produced from 12 moles of KClO3, you can use the given ratio in the balanced equation:
2 moles KClO3 produces 3 moles O2
Now, you can set up a proportion to solve for the unknown:
(3 moles O2 / 2 moles KClO3) = (x moles O2 / 12 moles KClO3)
Cross-multiplying, you get:
(3 moles O2) * (12 moles KClO3) = (2 moles KClO3) * (x moles O2)
36 moles O2 = 2x
Dividing both sides by 2, you get:
18 moles O2 = x
Therefore, from 12 moles of KClO3, you would get 18 moles of O2.