An infinitely long wire carries a current I=100A. Below the wire a rod of length L=10cm is forced to move at a constant speed v=5m/s along horizontal conducting rails. The rod and rails form a conducting loop. The rod has resistance of R=0.4ohms. The rails have neglibible resistance. The rod and rails are a distance a=10mm from the wire and in its non-uniform magnetic field as shown. What is the magnitude of the emf induced in the loop?

first, ampere's law

2PI * r * B=mu*current

solve that for B

Now Faradays law.

change Area/time= speed*.1m

EMF=B*speed*.1

check my thinking.

Notice in the description, r=a as I understand the "written" diagram.

hai @ Bobpursely i try with this hint u give us and i used mu=1.256*10^-6 but is not work , did u got green check using above formula ????? thanks !

0.001 V

Hello, can someone please explain the one with the thick metal slab???

really? is 0.001 the answer???

who have the answer?

0.001 is wrong @MARC , did u got green check with that value ??? plz help ???

that's what I thought, but then, the procedure indicated is not convincing.

Has anyone check the one with the 1mm diameter wire and current, which is the max B? I'm not sure how to calculate that.

hai any one got the ans of this

Two thin, infinitely long, parallel wires are lying on the ground a distance d=3cm apart. They carry a current Io=200A going into the page. A third thin, infinitely long wire with mass per unit length λ=5g/m carries current I going out of the page. What is the value of the current I in amps in this third wire if it is levitated above the first two wires at height h=10cm above them and at a horizontal position midway between them? plz help ???

anyone with this q:

A straight copper wire that is 1 milimeter in diameter carries a current of 20 miliamps. Whats the magnitude of the largest magnetic field created by this wire in Tesla?

I think B=uo.I/(2*pi*r)=8*10^-6

B at the perimeter, but I used r^2 instead of r, so I don't want to waste my last chance, anyone has tried that value? or feel like try it out and let me know if that is the correct value?