This is my homework assignment, and this isn't the real problem. I made this one up. so you could walk me through the steps so I can do the real problem!!
Thank you(:
What is the slope of the line that passes through the pair of points (3/2 , -2) and (-3, 7/3).
slope = (difference in the y values)/(difference in the x values), make sure you subract in the "same direction"
slope = (-2 - 7/3)/(3/2 - (-3)
= (-6/3 - 7/3)/(3/2 + 6/2)
=(-13/3) / (9/2)
= (-13/3)(2/9) = -26/27
by subtracting in the same direction ....
we could have done:
slope = (7/3 - (-2)) / (-3 - 3/2)
and obtain exactly the same anwer
Thank you so much Reiny I finally understand (: it means a lot!
To find the slope of a line passing through two points, you can use the formula:
slope (m) = (y2 - y1) / (x2 - x1)
Given the points (3/2, -2) and (-3, 7/3), we can label them as (x1, y1) and (x2, y2), respectively.
x1 = 3/2
y1 = -2
x2 = -3
y2 = 7/3
Now, let's substitute the values into the slope formula:
slope (m) = (y2 - y1) / (x2 - x1)
= ((7/3) - (-2)) / (-3 - (3/2))
Next, simplify the equation:
slope (m) = (7/3 + 2) / (-3 - (3/2))
= (7/3 + 2) / (-3 - (6/2))
= (7/3 + 6/3) / (-3 - (6/2))
= (13/3) / (-3 - 3)
Now, add the numerators and denominators:
slope (m) = (13/3) / (-6/1)
= (13/3) * (-1/6)
= -13 / 18
Therefore, the slope of the line passing through the points (3/2, -2) and (-3, 7/3) is -13/18.