Math

Factor:

(x^3)(z^6)-27y^9

81x^4-16y^4

2x^3+16y^3

  1. 👍 0
  2. 👎 0
  3. 👁 207
  1. You have the usual sum/difference of squares/cubes.

    (xz^2)^3 - (3y^3)^3
    = (xz^2-3y^3)((xz^2)^2 + (xz^2)(3y^3) + (3y^3)^2)

    Similarly, the others are

    (9x^2)^2 - (4y^2)^2
    and
    2(x^3 + (2y)^3)

    Just apply your formulas. If you get stuck, come on back and say where.

    1. 👍 0
    2. 👎 0

Respond to this Question

First Name

Your Response

Similar Questions

  1. Math

    9x^2+16y^2-18x+64y-71=0 find the coordinates of the center, the foci, and the vertices of this ellipse. 9x^2+16y^2-18x+64y-71=0 9x^2-18x+16y^2+64y=71 9(x^2-2x)+16(y^2+4y)=71 9(x^2-2x+1)+16(y^2+4y+4)=71

  2. math

    12x + 16y=1/5 & 13x + 24y =1/4,find value of x & y.

  3. Algebra

    What are the foci of the hyperbola with equation 16y^2-9x^2=144

  4. math

    How do I find vertex, focus and directrix for the following functions? y^2−16y=12x−8^2 x^2+16x=4y−24 (x−2)^2=12(y−2)

  1. Algebra 2

    (x^2+8xy+16y^2)^(1/3)*(x+4y)^(1/3)

  2. algebra

    Special factorization Completely factor the following expressions 250x^3-128 X^6-1 X^6+1 x^2-8xy+16y^2-25 16x^4a-y^8a ((8x^3)/125)+(64/y^3) I was given a set on how to do this skill, but it didn't really cover on how to attack

  3. Algebra.

    Help? -Solve Polynomial Equations By factoring. 1. x^6-25x^4=0 2. y^3-3y^2=16y-48 3. x^3+2x^2-9x-18=0 4. x^3+x^2-4x-4=0 5. x^3-7x^2=-5x-30 6. a^4+2a^3+a^2=0 7. 3n^4-4n^2=-1 8. 8x^5+10x^4=4x^3+5x^2 9. 2n^4-9n^2+4=0 10. 8y^4 / y^2 -

  4. Calculus

    What is the largest rectangle that can be inscribed in the first quadrant of the ellipse 9x^2+16y^2=144?

  1. Math- Algebra II

    9x^4/16y^6 How to I simplify it must be written in exponential form and no negative exponents. HELP

  2. alg.

    solve the system by addition: -5x-9y = -5 x+5y=-15 I've tried this one over and over, but I can't seem to get the right answer. I don't even really know where to start. each time i try to do it, i go about it a little differently

  3. math-algebra

    Simplify: [(4x^3y)(4^2xy)^-1]/(4xy^2) A. x /16y^2 B. 16x/y^2 C. x^2/16y D. y/16x^2

  4. Algebra

    hello.i have to factor this expression. 3y^2-16y-12 i did my work and i got (y-4)(y+1) is it right?

You can view more similar questions or ask a new question.