A battery is connected to the endpoints A and B of a homogeneous wire. Using an ammeter one finds that a current I = 1.5 A flows through the conductor. Then, the wire is bent in the form of a circle and the same battery is connected to points A and B.
What is the current in Amps flowing through point C in this case? You may neglect the internal resistance of the battery.
This just how its picture, since i couldn't attach a picture
A -------- B
C
/ \
/ \
A B
\ /
\____/
To determine the current flowing through point C when the wire is in the form of a circle, we can use the concept of conservation of charge. According to this principle, the amount of charge entering a section of the wire should be equal to the amount of charge leaving that section.
In the given scenario, the current flowing through points A and B, when the wire is in a straight line, is 1.5 A. Since the wire is homogeneous, this means that 1.5 Amps of current is passing through any point along the wire.
Now, when the wire is bent in the form of a circle, we can analyze the situation as follows:
1. The current entering point A of the circle is still 1.5 A, as the current remains constant in a homogeneous wire.
2. At point C, we can consider a small section of the wire. The total current entering this section is 1.5 A.
3. Since the wire is in the form of a circle and is homogeneous, the current splits equally at point C. This means that 0.75 A flows clockwise and 0.75 A flows counterclockwise through the section containing point C.
Therefore, the current flowing through point C in this case is 0.75 A (clockwise) or 0.75 A (counterclockwise).