2x+6y=60

in determinng the x and y intercept I came up with the order pair 0,-10 Is this correct?

To determine the x-intercept and y-intercept, we set one variable to zero at a time and solve the equation.

For the x-intercept, we set y to zero and solve for x:
2x + 6(0) = 60
2x = 60
x = 60/2
x = 30

For the y-intercept, we set x to zero and solve for y:
2(0) + 6y = 60
6y = 60
y = 60/6
y = 10

So the correct x-intercept is (30, 0) and the correct y-intercept is (0, 10), not (0, -10).

To determine the x-intercept, we set y equal to 0 and solve for x. Similarly, to determine the y-intercept, we set x equal to 0 and solve for y.

For the equation 2x + 6y = 60:
To find the x-intercept, substitute y = 0 into the equation:
2x + 6(0) = 60
2x + 0 = 60
2x = 60
x = 60/2
x = 30

So, the x-intercept is (30, 0).

Now let's find the y-intercept by substituting x = 0 into the equation:
2(0) + 6y = 60
0 + 6y = 60
6y = 60
y = 60/6
y = 10

Therefore, the y-intercept is (0, 10).

The ordered pair (0,-10) you mentioned does not lie on the line represented by 2x + 6y = 60. The correct x-intercept is (30, 0) and the correct y-intercept is (0, 10).