for a thermodynamics lab, I have to graph the ln K vs. 1/T, so does the ln K go on the y-axis and the 1/T go on the x-axis?
I HAVE NO CLUE
answered above by jai
Yes, for the graph of ln K vs. 1/T, the ln K is typically plotted on the y-axis while 1/T is plotted on the x-axis.
To understand why, let's break it down:
In thermodynamics, the equilibrium constant (K) relates to the temperature (T) through the equation:
ln K = -ΔH/R * (1/T) + ΔS/R
where ΔH is the enthalpy change, ΔS is the entropy change, and R is the ideal gas constant.
By rearranging the equation, we can see that ln K is proportional to -1/T:
ln K = -ΔH/R * (1/T) + ΔS/R
This means that the natural logarithm of the equilibrium constant (ln K) is linearly related to the inverse temperature (1/T).
When plotting ln K vs. 1/T, this relationship will result in a linear graph. The slope of the line will be determined by -ΔH/R, and the y-intercept will be ΔS/R.
By plotting ln K on the y-axis and 1/T on the x-axis, you can easily visualize and interpret the relationship between ln K and 1/T.