Coefficient of volume expansion of some liquids(a/˚C)
Alcohol=1.1x〖10〗^(-4)
Glycerin=5.0x〖10〗^(-4)
Water=3.7x〖10〗^(-4)
Ether=1.63x〖10〗^(-4)
Mercury= 1.1x〖10〗^(-4
A glass flask is completely filled w/ 200cc of mercury at 15˚C. If it is heated to 85˚C, how many cc of mercury will flow out?
Overflow = The increase in vol.
Same procedure as previous problem.
To calculate the change in volume of mercury when it is heated from 15˚C to 85˚C, we need to use the coefficient of volume expansion of mercury. From the given data, the coefficient of volume expansion of mercury is 1.1x10^(-4) per ˚C.
The formula to calculate the change in volume is given by:
ΔV = V₀ * α * ΔT
Where:
ΔV = Change in volume
V₀ = Initial volume
α = Coefficient of volume expansion
ΔT = Change in temperature
Here, V₀ is 200 cc (the initial volume of the mercury in the flask), α is 1.1x10^(-4) (coefficient of volume expansion of mercury), and ΔT is 85˚C - 15˚C = 70˚C (change in temperature).
Substituting these values into the formula, we get:
ΔV = 200 cc * 1.1x10^(-4) per ˚C * 70 ˚C
Calculating this, we get:
ΔV = 200 cc * 1.1x10^(-4) per ˚C * 70 ˚C
= 1.54 cc
Therefore, 1.54 cc of mercury will flow out of the flask when it is heated from 15˚C to 85˚C.