Coefficient of volume expansion of some liquids(a/˚C)
Alcohol=1.1x〖10〗^(-4)
Glycerin=5.0x〖10〗^(-4)
Water=3.7x〖10〗^(-4)
Ether=1.63x〖10〗^(-4)
Mercury= 1.1x〖10〗^(-4)
How much water overflows when a pyrex vessel filled to the grim with 1 liter(100cm cube) of water at 20˚ C is heated 90˚C?
Overflow = a(T-To)Vo
Overflow=3.7*10^-4(90-20)100=2.59 cm^3
To calculate the volume of water that overflows when the pyrex vessel is heated from 20˚C to 90˚C, we need to use the coefficient of volume expansion for water.
The coefficient of volume expansion (denoted as α) represents how much the volume of a substance expands or contracts with a change in temperature. For water, the coefficient of volume expansion is given as 3.7x10^(-4) per ˚C.
Given:
Initial volume of water (V_initial) = 1 liter = 100 cm³
Change in temperature (ΔT) = 90˚C - 20˚C = 70˚C
To calculate the overflow volume, we need to determine the change in volume of the water due to the increase in temperature.
ΔV = V_initial * α * ΔT
Substituting the values:
ΔV = 100 cm³ * (3.7x10^(-4) ˚C^(-1)) * 70˚C
Calculating:
ΔV = 100 cm³ * (3.7x10^(-4)) * (70)
ΔV ≈ 0.259 cm³
Therefore, approximately 0.259 cm³ of water will overflow from the pyrex vessel when it is heated from 20˚C to 90˚C.