A 0.40 g fruit in a tree has a gravitational potential energy of 200 J. How high from the ground is the fruit?
m*g*h= potencial energy
mass needs to be in kilograms
g= 9.81 m/s^2
h in meters
PE in J
solve for h
i think that the mass of the fruit is 0.40 Kg instead of grams
To determine the height of the fruit from the ground, we need to use the formula for gravitational potential energy:
Gravitational potential energy (PE) = mass (m) * gravity (g) * height (h)
In this case, we are given the mass of the fruit (m = 0.40 g) and the gravitational potential energy (PE = 200 J). The acceleration due to gravity (g) is approximately 9.8 m/s².
First, we need to convert the mass of the fruit to kilograms since the unit of mass in the formula is in kilograms:
0.40 g = 0.40 * 10^-3 kg (1 gram = 10^-3 kilograms)
Next, we can rearrange the formula to solve for the height (h):
h = PE / (m * g)
Substituting the given values:
h = 200 J / (0.40 * 10^-3 kg * 9.8 m/s²)
Now we can calculate the height:
h = 200 J / (0.40 * 10^-3 kg * 9.8 m/s²)
h ≈ 51.02 meters
Therefore, the fruit is approximately 51.02 meters high from the ground.