For a motor vehicle travelling at r miles per hour, the distance d in feet required to stop at approximately d=0.05r^2+r. If a school bus is traveling at 45mph how many feet to, the nearest foot,would it travel before coming to a halt.
d = 0.05r^2 + r
Substitute r = 45:
d = 0.05(45)^2 + 45
d = 101.25 + 45
d = 146.25 ft
To the nearest foot,
d = 146 ft
Hope this helps :3
Thank you, Jai!
To find the distance required to stop a motor vehicle traveling at a certain speed, you can use the given equation d = 0.05r^2 + r, where d represents the distance in feet and r represents the speed in miles per hour.
In this case, we are given that the school bus is traveling at 45 mph, so we need to substitute this value into the equation and solve for d:
d = 0.05r^2 + r
d = 0.05(45^2) + 45
d = 0.05(2025) + 45
d = 101.25 + 45
d = 146.25
Therefore, the school bus would travel approximately 146.25 feet before coming to a halt.
Rounding this value to the nearest foot, the school bus would travel 146 feet before coming to a halt.