(c) ____Cl2(g) + ____KBr(aq)h____Br2(l ) + ____KCl (aq)
(d) ____CH4(g) + ____O2(g)h____CO2(g) + ____H2O(l )
To balance the chemical equations provided in parts (c) and (d), we need to determine the coefficients that precede each compound.
In chemical equations, the coefficients indicate the relative number of molecules or moles of each substance involved in the reaction. By ensuring that the number of atoms on each side of the equation is equal, we can balance the equation.
Let's start with part (c):
To balance the equation: Cl2(g) + KBr(aq) → Br2(l) + KCl(aq)
We can follow these steps:
Step 1: Count the number of atoms of each element on both sides of the equation.
Before:
Cl: 2
K: 1
Br: 1
After:
Cl: 1
K: 1
Br: 2
Step 2: Balance the atoms on either side by adding coefficients.
Cl2(g) + 2KBr(aq) → Br2(l) + 2KCl(aq)
Now, let's move on to part (d):
To balance the equation: CH4(g) + O2(g) → CO2(g) + H2O(l)
Step 1: Count the number of atoms of each element on both sides of the equation.
Before:
C: 1
H: 4
O: 2
After:
C: 1
H: 2
O: 3
Step 2: Balance the atoms on either side by adding coefficients.
CH4(g) + 2O2(g) → CO2(g) + 2H2O(l)
This balanced equation shows that one molecule of methane (CH4) reacts with two molecules of oxygen gas (O2) to produce one molecule of carbon dioxide (CO2) and two molecules of water (H2O).
Remember, balancing chemical equations requires practice and understanding of stoichiometry. It involves adjusting coefficients to ensure equal numbers of atoms on both sides.