when 2.750 g of the oxide of lead is heated to a high temperature,it decomposes to produce 0.0640 g of oxygen gas and 2.686 g of some new lead oxide compound.How can you use this data to determine the formula of the new compound?

Well, it seems like lead is a bit of a drama queen! Let's break down the data and figure out the formula of this new compound.

So, we have 2.750 g of the original lead oxide, which decomposes into 0.0640 g of oxygen gas. That means that the remaining mass must belong to the new lead oxide compound.

Subtracting the mass of the oxygen gas from the original mass of lead oxide, we get:

2.750 g - 0.0640 g = 2.686 g

Now, we know that the new lead oxide compound has a mass of 2.686 g. To find the formula, we need to determine the ratio of lead to oxygen.

The molar mass of oxygen gas (O₂) is about 32 g/mol, and the molar mass of lead (Pb) is about 207 g/mol.

Considering these molar masses, we can calculate the number of moles of oxygen using its mass:

0.0640 g / 32 g/mol = 0.002 mol of oxygen

Since oxygen has a charge of -2, in order to balance the equation, lead must have a charge of +2.

Now, let's calculate the number of moles of lead in the new compound:

2.686 g / 207 g/mol = 0.013 mol of lead

The ratio of lead to oxygen in the new compound, based on moles, is:

0.013 mol lead : 0.002 mol oxygen

To simplify this ratio, we can multiply both numbers by 1000:

13 mol lead : 2 mol oxygen

And to get whole number ratios, let's divide both numbers by 2:

6.5 mol lead : 1 mol oxygen

By rounding it off, we find that the ratio of lead to oxygen in the new compound is approximately:

6 mol lead : 1 mol oxygen

So, based on this ratio, we can determine the formula of the new compound to be Pb₆O. Voilà!

Just remember, always be on the lookout for dramatic reactions when dealing with lead!

To determine the formula of the new lead oxide compound, we need to analyze the amounts of lead and oxygen in the reactant and products.

Let's break down the given information:
- Mass of the original oxide of lead (reactant) = 2.750 g
- Mass of oxygen gas produced = 0.0640 g
- Mass of the new lead oxide compound = 2.686 g

1. Calculate the mass of lead in the original oxide of lead:
The mass of oxygen can be subtracted from the mass of the original oxide of lead:
Mass of lead = Mass of the original oxide of lead - Mass of oxygen gas
Mass of lead = 2.750 g - 0.0640 g
Mass of lead = 2.686 g

2. Determine the number of moles of lead and oxygen:
To find the number of moles, we divide the mass of each element by its molar mass.
The molar masses (in g/mol) are:
- Lead (Pb) = 207.2 g/mol
- Oxygen (O) = 16.00 g/mol

Number of moles of lead = Mass of lead / Molar mass of lead
Number of moles of lead = 2.686 g / 207.2 g/mol
Number of moles of lead ≈ 0.0129 mol

Number of moles of oxygen = Mass of oxygen / Molar mass of oxygen
Number of moles of oxygen = 0.0640 g / 16.00 g/mol
Number of moles of oxygen ≈ 0.0040 mol

3. Determine the mole ratio of lead to oxygen:
Based on the balanced equation for the decomposition reaction, we can determine the mole ratio of lead to oxygen. Let's assume the formula of the new compound is PbOx, where x is the subscript representing the number of oxygen atoms.

From the data, we have:
Moles of lead = 0.0129 mol
Moles of oxygen = 0.0040 mol

Divide the mole quantities by the smaller value (0.0040 mol) to determine the ratio:
Lead: Oxygen = 0.0129 mol / 0.0040 mol ≈ 3.23

The ratio suggests that there are approximately 3.23 times as many lead atoms as oxygen atoms in the new compound.

4. Determine the empirical formula of the new lead oxide compound:
The empirical formula gives the simplest whole-number ratio of elements present in a compound. In this case, since the ratio is close to 3.23, we round it to the nearest whole number, which is 3. So, the empirical formula is Pb3O.

Therefore, the formula of the new lead oxide compound is Pb3O.

To determine the formula of the new lead oxide compound, you need to analyze the mass relationship between the reactants (original oxide of lead) and the products (oxygen gas and the new lead oxide compound).

First, let's write a balanced chemical equation for the reaction:

2PbO -> 2Pb + O2

From the equation, you can see that 2 moles of lead oxide (PbO) will produce 2 moles of lead (Pb) and 1 mole of oxygen gas (O2). The equation is balanced in terms of moles.

Now, let's use the given data:

Mass of original lead oxide (PbO) = 2.750 g
Mass of oxygen gas (O2) = 0.0640 g
Mass of new lead oxide compound = 2.686 g

To find the moles of each substance, we need to divide the mass by the molar mass.

The molar mass of PbO can be found by adding the atomic masses of lead (Pb) and oxygen (O):
Pb: atomic mass = 207.2 g/mol
O: atomic mass = 16.0 g/mol

So, the molar mass of PbO = 207.2 + 16.0 = 223.2 g/mol.

Now, calculate the moles of each substance:

Moles of original lead oxide (PbO) = mass / molar mass = 2.750 g / 223.2 g/mol
Moles of oxygen gas (O2) = mass / molar mass = 0.0640 g / 32.0 g/mol
Moles of new lead oxide compound = mass / molar mass = 2.686 g / unknown molar mass of the new compound (let's call it x g/mol).

To determine the moles of the new lead oxide compound, we can use the conservation of mass principle. The total moles of reactants should be equal to the total moles of products:

Moles of reactants = Moles of products
Moles of PbO = Moles of Pb + Moles of new compound

From the balanced chemical equation, we know that 2 moles of PbO decompose to produce 2 moles of Pb and 1 mole of O2. So, we have:

2 * Moles of PbO = 2 * Moles of Pb + Moles of O2

Rearranging the equation, we get:

Moles of PbO - Moles of Pb = Moles of O2

Substituting the values:

2.750 g / 223.2 g/mol - Moles of Pb = 0.0640 g / 32.0 g/mol

Now, solve for the moles of Pb:

Moles of Pb = 2.750 g / 223.2 g/mol - 0.0640 g / 32.0 g/mol

Next, substitute this value of moles of Pb into the equation:

2 * Moles of PbO = 2 * (2.750 g / 223.2 g/mol - 0.0640 g / 32.0 g/mol) + Moles of new compound

Since we know the moles of PbO and moles of O2, we can solve for the moles of the new lead oxide compound:

Moles of new lead oxide compound = 2 * Moles of PbO - 2 * Moles of Pb

Finally, calculate the molar mass of the new lead oxide compound:

Mass of new lead oxide compound / Moles of new lead oxide compound = unknown molar mass of new compound / 1 (since 1 mole of compound is equal to its molar mass in grams).

Rearrange the equation to solve for the unknown molar mass of the new compound:

Unknown molar mass of new compound = Mass of new lead oxide compound / Moles of new lead oxide compound