Line m passes through (2,5) and (-3,-2) Find the slope of a line that is perpendicular to line m.
line m has slope ∆y/∆x = (-2-5)/(-3-2) = 7/5
the perpendicular line's slope is the negative reciprocal, or -5/7
m = (-2-5)/(-3-2)
m = 7/5
Perpendicular m = -5/7
To find the slope of a line perpendicular to line m, we first need to find the slope of line m.
The slope of a line passing through two points (x1, y1) and (x2, y2) can be found using the formula:
slope = (y2 - y1) / (x2 - x1)
For line m passing through (2,5) and (-3,-2), we can use these points to calculate the slope:
slope of line m = (-2 - 5) / (-3 - 2)
= (-7) / (-5)
= 7/5
The slope of line m is 7/5.
To find the slope of a line perpendicular to line m, we need to take the negative reciprocal of the slope of line m.
The negative reciprocal of 7/5 is -5/7.
Therefore, the slope of a line perpendicular to line m is -5/7.
To find the slope of a line perpendicular to line 𝑚, we need to first determine the slope of line 𝑚. The slope of a line passing through two points can be found using the formula:
𝑚 = (𝑦₂ - 𝑦₁) / (𝑥₂ - 𝑥₁)
Where (𝑥₁, 𝑦₁) and (𝑥₂, 𝑦₂) are the coordinates of the two points on line 𝑚.
Given the points (2, 5) and (-3, -2), we can plug these values into the formula:
𝑚 = (-2 - 5) / (-3 - 2)
= (-7) / (-5)
= 7/5
The slope of line 𝑚 is 7/5.
To find the slope of a line perpendicular to line 𝑚, we need to take the negative reciprocal of the slope. The negative reciprocal is found by flipping the fraction and changing its sign.
Therefore, the slope of the line perpendicular to line 𝑚 is:
𝑚_perpendicular = -1 / (7/5)
= -5/7
So, the slope of the line perpendicular to line 𝑚 is -5/7.