for this question A sample of air has a volume of 140.0 mL at 67 degrees celcius. At what temperature would its volume 50.0 mL at constant pressure
I did
140.0 ml... 67+273=340
T2... 50.0
140.0=50.0
340=T2
340*50.0/140.0=121.4
This question i don't get because of the scientific notation. A sample of oxygen that occupies 1.00 x 10^6 mL at 575 mm Hg is subjected to a pressure of 1.25 atm. What will the final volume of the sample be if the temp is held constant?
The first one is ok EXCEPT that if your prof is a stickler for significant figures, you will get points counted off if not the entire question. The smallest number of significant figures is 3 (50.0, 340) so the most s.f. you are allowed in the answer is 3; therefore, you would round the answer to 121. ALSO, some profs will count off if you don't have units; therefore, the complete answer would be 121 Kelvin.
For the second problem, 10^6 just means to add 6 zeros to 1 (which would be 1,000,000). Or you can key in the number with scientific notation to your calculator and let it keep track of the decimal. USUALLY, a number expressed as 1.00 x 10^6 mL means your prof looks at s.f.
ok i get that now.. but now im still confused with how to solve the problem because i don't see where it talks about temperature.
Sure. It says the temperature is held constant. This is a pressure/volume problem. Done the same way except
P1V1 = P2V2.
By the way, do you know how to keep all these formulas straight? Do it this way.
The general formula is
(P1V1)/T1 = (P2V2)/T2
If T is constant, just cover up T1 and T2 with your fingers (or mentally) and you have P1V1 = P2V2 which is Boyle's Law.
If P is held constant, cover up P1 and P2 with your fingers (or mentally), and you have V1/T1 = V2/T2 which is Charles' Law.
If V is held constant, covert up V1 and V2 with yur fingers (or mentally) and you have P1/T1 = P2/V2. Easy, huh?
You only need to memorize the general formula that contains all the variable and tailor it to fit the problem. And, of course, you must remember that T always goes in with Kelvin.
If V is held constant, covert up V1 and V2 with yur fingers (or mentally) and you have P1/T1 = P2/V2. Easy, huh?
I made a goof here. This should read, if V is held constant, cover up V1 and V2 with your fingers (or mentally) and you have P1/T1 = P2/T2
My fingers sometimes get ahead of my brain.
well im sure u can tell chemistry is my weakest subject because im still confused :/...
so would it be 1000000= 575
1.25= t2?
Why do you want to solve for t? It SAYS t is constant so we don't care what it is. And you haven't used the pressure at all.
You didn't do what I said. Just follow the guide lines.
P1V1/T1 = P2V2/T2.
Now, since T is constant, cover T1 and T2 with your fingers, or mentally, and we are left with
P1V1 = P2V2
Now look at the problem.
V1 = 1 x 10^6 mL
P1 = 575 mm Hg
V2 = ?? mL.
P2 = 1.25 atm.
Right away you see that the units on pressure don't match. You must change mm Hg to atmospheres OR change atmospheres to mm Hg. The conversion factor is 760 mm = 1 atm. The easy one to change is P1 so 575/760 = 0.756 atm.
Then P1V1 = P2V2
0.756*1x10^6 = 1.25*V2 and solve for V2.
ok thank you for all of your help tonight.. i really appreciate it!
You're welcome.
p1v1/t1=p2vp/t2;v2
To solve the question about the final volume of the sample, you can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
Let's break down the given information:
Initial volume (Vi) = 1.00 x 10^6 mL
Initial pressure (Pi) = 575 mm Hg
Final pressure (Pf) = 1.25 atm (the pressure given in the question)
Final volume (Vf) = To be determined
Using Boyle's Law, you can set up the equation: Pi * Vi = Pf * Vf.
Substituting the given values, we get:
575 mm Hg * 1.00 x 10^6 mL = 1.25 atm * Vf
To solve for Vf, you can convert the initial volume and pressure to the same units as the final pressure and rearrange the equation. Here are the conversions you need:
1 atm = 760 mm Hg (standard atmospheric pressure)
Converting the initial pressure:
575 mm Hg * (1 atm / 760 mm Hg) = Pi in atm
Pi = 0.756 atm
Substituting this value into the equation:
0.756 atm * 1.00 x 10^6 mL = 1.25 atm * Vf
Now, you can solve for Vf:
Vf = (0.756 atm * 1.00 x 10^6 mL) / 1.25 atm
Simplifying the expression:
Vf = 0.6048 x 10^6 mL / 1.25
Vf = 0.4848 x 10^6 mL
Vf = 4.848 x 10^5 mL
Therefore, the final volume of the sample, when the temperature is held constant, is 4.848 x 10^5 mL.