When 23.18 g of element A react completely with 48.08 g of E, compound A2E is formed. When 11.70 g of A react with 22.57 g of G, compound AG is formed. If elements E and G react to form EG3, what mass in grams of G is required to react with 12.97 g of E?
The molar mass of E is 115.988 g mol-1.
From The problem we know
2A + E ==> A2E
We have mols E = g/molar mass = 48.08/115.988 = 0.4145 mols.
mols A must be twice that
0.4145 x 2 = ??
molar mass A = g/mol = 23.18/.82905 = ??
Similarly, the reaction A + G is done to determine the molar mass of G.
Similarly, the reaction of E and G is done to determine the grams G that reacts.
Post your work if you get stuck.
To find the mass of G needed to react with 12.97 g of E, we will follow similar steps as before to determine the moles of E and A2E.
1. Calculate the moles of E:
Moles of E = mass of E / molar mass of E
Moles of E = 12.97 g / 115.988 g/mol
Moles of E = 0.1119 mol
2. Use the stoichiometry of the reaction A2E to determine the moles of A:
Since the balanced equation is 2A + E → A2E, the ratio of moles of A to moles of E is 2:1.
Moles of A = 0.1119 mol x 2
Moles of A = 0.2238 mol
3. Use the stoichiometry of the reaction A + G to determine the moles of G:
Since the balanced equation is A + G → AG, the ratio of moles of A to moles of G is 1:1.
Moles of G = 0.2238 mol
4. Calculate the mass of G needed:
Mass of G = Moles of G x Molar mass of G
Mass of G = 0.2238 mol x molar mass of G
Mass of G = 0.2238 mol x 115.988 g/mol
Mass of G = 25.92 g
Therefore, 25.92 grams of G is required to react with 12.97 grams of E.