If point A is (2,4) and point B is (3,2) and slope is -2 what would the equation be in standard form?
Having trouble with this problem!
Once again, the same kind of question as before.
step1: find slope
(you did that correctly and got m = -2)
step2:
use y-y1 = m(x-x1) , where (x1, y1) is either of the given points
using (2,4)
y-4 = -2(x-2)
y-4 = -2x + 4
standard form has both x and y terms on the left, the constant on the right.
so....
2x + y = 8
(using (3,2) has to give you the same equation, try it.)
I usually use the point not used to sub in my equation, to see if it satisfies the equation.
It does!
Let me see if I remember this... I believe you plug in one of the points into the point slope formula
y-y1=m(x-x1)
(2,4) x1=2 and y1=4 m=slope in this case -2
I hope this help
To find the equation of a line in standard form, we can use the formula:
Ax + By = C
where A, B, and C are constants.
First, let's find the slope-intercept form of the equation using the given slope and one of the points (A or B). The slope-intercept form is given by:
y = mx + b
where m is the slope and b is the y-intercept.
Given slope = -2
Using point A(2, 4), substitute the values into the equation:
4 = -2(2) + b
Simplify:
4 = -4 + b
Add 4 to both sides:
8 = b
Now we have the y-intercept (b = 8) and the slope (m = -2).
Substituting these values into the slope-intercept form equation, we get:
y = -2x + 8
To convert this equation into standard form (Ax + By = C), we need to ensure that the coefficients A, B, and C are integers.
Multiply through by -1 to make the coefficient of x positive:
-y = 2x - 8
Now, rearrange the equation by adding "y" to both sides and move the constant term to the other side:
2x + y = -8
Finally, we have the equation in standard form:
2x + y = -8.