8.10-L container holds a mixture of two gases at 45 °C. The partial pressures of gas A and gas B, respectively, are 0.153 atm and 0.882 atm. If 0.110 mol a third gas is added with no change in volume or temperature, what will the total pressure become?
the partial pressure of the third gas will be
P=nRT/V solve that, then add it to the sum of the first two pressures.
Dinah, I worked one JUST LIKE this yesterday for you (both the short way and the long way). You should be able to see the connection and not ask for help when it's the same type problem.
To solve this problem, we need to apply Dalton's law of partial pressures.
According to Dalton's law of partial pressures, the total pressure of a mixture of gases is equal to the sum of the partial pressures of each individual gas.
In this case, the partial pressure of gas A is 0.153 atm, and the partial pressure of gas B is 0.882 atm. We are also given that the container has a total volume of 8.10 L and is at a temperature of 45 °C.
Since the volume and temperature remain constant when the additional gas is added, we can assume that the total moles of gas in the container will increase by 0.110 mol.
Now, let's calculate the moles of gas A and gas B before the addition of the third gas:
Moles of gas A = partial pressure of gas A * volume / (gas constant * temperature)
= 0.153 atm * 8.10 L / (0.0821 * (45 + 273) K)
≈ 0.0049 mol
Moles of gas B = partial pressure of gas B * volume / (gas constant * temperature)
= 0.882 atm * 8.10 L / (0.0821 * (45 + 273) K)
≈ 0.028 mol
Now, let's calculate the total moles of gas after adding the third gas:
Total moles after addition = moles of gas A + moles of gas B + moles of third gas
= 0.0049 mol + 0.028 mol + 0.110 mol
= 0.142 mol
Finally, we can calculate the total pressure using Dalton's law of partial pressures:
Total pressure = (total moles * gas constant * temperature) / volume
= (0.142 mol * 0.0821 * (45 + 273) K) / 8.10 L
≈ 1.21 atm
Therefore, the total pressure in the container will become approximately 1.21 atm after adding the third gas.