A trailer with a mass of 2.00x 10^3 kg is pulled by a truck with a mass of 3.00 x 10^3 kg. If the applied force is 8750 N and the frictional force exerted by the road is 2560 N, what is the acceleration of the truck and trailer?
a=(F-F(fr))/(m1+m2)
To find the acceleration of the truck and trailer, we need to apply Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration (F = m * a).
In this case, the net force is the difference between the applied force and the frictional force:
Net force = Applied force - Frictional force
Let's calculate the net force first:
Net force = 8750 N - 2560 N
Net force = 6190 N
Now, we can calculate the total mass of the truck and trailer:
Total mass = Mass of truck + Mass of trailer
Total mass = 3.00 x 10^3 kg + 2.00 x 10^3 kg
Total mass = 5.00 x 10^3 kg
Finally, we can calculate the acceleration using Newton's second law:
Acceleration = Net force / Total mass
Acceleration = 6190 N / 5.00 x 10^3 kg
Acceleration = 1.238 m/s^2
Therefore, the acceleration of the truck and trailer is approximately 1.238 m/s^2.