Math

So if point A is (2,4) and point B is (3,2) and slope is -2 how would I find the x and y intercepts?

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  1. (y-4)/(x-2) = (2-4)/(3-2)
    y-4 = -2(x-2)
    y = -2x+8

    if x=0, y=8
    if y=0, x=4

    so, the intercepts are (0,8) and (4,0)
    I'm hoping you can figure out which is which

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  2. Is this the continuation of your question? :)
    In the previous question, we know the slope is -2, and therefore we use the point-slope formula to get the equation:
    y - y1 = m(x - x1)
    We only need the slope and one point to get the equation. Let's use the point(2,4). Substituting,
    y - 4 = -2(x - 2)
    y - 4 = -2x + 4
    y = -2x + 8
    To get the x-intercept, let y = 0 and solve for x:
    0 = -2x + 8
    2x = 8
    x = 4
    x-intercept is at (4,0).

    To get y-intercept, let x = 0 and solve for y:
    y = -2(0) + 8
    y = 8
    y-intercept is at (0,8).

    Hope this helps :)

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  3. Okay!! So would y=-2x+8 be the equation?

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  4. Yes. :) The equation containing (2,4) with slope equal to -2 is y = -2x + 8.

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  5. So now I then have to put it in a equation of line parallel thorough (-2,0). How would I do that?

    Then after that I would have to put equation of line perpendicular through y-intercept. How would I do that too?

    Thanks so much for help me I really don't understand this!!

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  6. you know the parallel line also has slope -2, so using the point-slope form, that is

    (y-0) = -2(x-2)
    .......................
    the perpendicular line has slope -1/(-2) = 1/2

    Figure the y-intercept and you again have a point and a slope.

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