A 6.48-L cylinder contains 1.48 mol of gas A and 4.80 mol of gas B, at a temperature of 33.4 °C. Calculate the partial pressure of each gas in the cylinder. Assume ideal gas behavior.
Use PV = nRT; substitute n = 1.48 and solve for p gas A. Substitute n = 4.80 and solve for p gas B.
Remember T must be in kelvin.