An infinitely long wire carrying a current of 2 A is bent at a right angle as shown in the Figure. What is the magnetic field a point P, 10 cm from the corner?

To find the magnetic field at a point P, 10 cm from the corner of the wire, we can use the Biot-Savart Law. The law states that the magnetic field at a point due to a current-carrying wire is directly proportional to the current, the length of the wire segment, and inversely proportional to the square of the distance between the point and the wire segment.

Here's how you can apply the Biot-Savart Law to find the magnetic field at point P:

1. Identify the wire segments contributing to the magnetic field at point P. In this case, we have two wire segments, one going straight up and the other going straight to the right.

2. Calculate the magnetic field contribution from each segment separately using the Biot-Savart Law. The magnetic field at point P due to each wire segment is given by the formula:

dB = (μ₀ / 4π) * (I * dl × r) / r²

Where:
- dB is the magnetic field contribution at point P
- μ₀ is the permeability of free space (approximately 4π × 10⁻⁷ T*m/A)
- I is the current in the wire (2 A)
- dl is a small length element of the wire segment
- r is the distance vector from the dl element to point P

3. Calculate the magnetic field contribution from each wire segment separately, and add them vectorially to obtain the total magnetic field at point P.

B_total = B₁ + B₂

Where:
- B_total is the total magnetic field at point P
- B₁ is the magnetic field contribution at point P due to the first wire segment
- B₂ is the magnetic field contribution at point P due to the second wire segment

Note: The direction of the magnetic field is perpendicular to both the wire segment and the vector r, and follows the right-hand rule.

By following these steps and performing the necessary calculations, you can find the magnetic field at point P, 10 cm from the corner of the wire.