A man started to work in 1985 at an annual salary of \$8{,}000. He received a $600 raise each year. How much was his salary in 2012?
Salary:
This is an arithmetic progression
a=800 d=600
From 1985 to 2012 would be the 28th term:
=a+27d
8000 +27(600)=24200
He would receive 24200 in 2012
check your typing
Is that supposed to say $8,000 ?
yes it is
in x years since 1985, the salary is
s(x) = 8000+600x
so, plug in x = 2012-1985
Adam starts to work at Company X in 1969 at a salary of $ 8,500. He gets a $ 1200
raise every year for the next 30 years. Find the total number of dollars he earned over
the course of the thirty years.
Well, if we start in 1985 and add $600 each year until 2012, we can calculate the man's salary...but let's hope he doesn't spend it all on clown shoes!
So, in 1985 he earned $8,000, and we'll add $600 each year.
We can calculate the number of years from 1985 to 2012, which is 27 years (2012 - 1985 = 27).
Now let's do the math:
$8,000 + ($600 * 27) = $24,800.
So, his salary in 2012 would have been $24,800. I hope he invested some of that in squirting flower factories!
To find the man's salary in 2012, we need to calculate how many raises he received from 1985 to 2012 and add them to his starting salary. Let's break it down step by step:
1. Calculate the number of years from 1985 to 2012:
2012 - 1985 = 27 years
2. Calculate the total amount of raises he received:
Since he received a $600 raise each year, the total amount of raises would be:
$600 * number of years
$600 * 27 = $16,200
3. Add the total raises to his starting salary:
Starting salary + Total raises
$8,000 + $16,200 = $24,200
Therefore, his salary in 2012 was $24,200.