What's your normal body temperature? It may not be 98.6°F, the oft-quoted average that was determined in the nineteenth century. A more recent study has reported an average temperature of 98.2°F. What is the difference between these averages, expressed in Celsius degrees?

To calculate the difference between two temperatures in Celsius degrees, you need to convert the Fahrenheit temperatures to Celsius. Here's how you can do it:

1. Convert 98.6°F to Celsius:
- Deduct 32 from the Fahrenheit temperature: 98.6 - 32 = 66.6
- Multiply the result by 5/9: 66.6 * (5/9) ≈ 37°C

2. Convert 98.2°F to Celsius:
- Deduct 32 from the Fahrenheit temperature: 98.2 - 32 = 66.2
- Multiply the result by 5/9: 66.2 * (5/9) ≈ 36.8°C

Now we have the average body temperature in Celsius: 37°C (for 98.6°F) and 36.8°C (for 98.2°F).

To find the difference between these two averages, subtract the lower temperature from the higher temperature:

37°C - 36.8°C ≈ 0.2°C

Therefore, the difference between these averages, expressed in Celsius degrees, is approximately 0.2°C.

To find the difference between the averages in Celsius degrees, we need to convert Fahrenheit to Celsius.

To convert Fahrenheit to Celsius, we can use the formula:
°C = (°F - 32) * (5/9)

First, let's convert the average temperature of 98.6°F to Celsius:
°C = (98.6 - 32) * (5/9)
°C = 66.6 * (5/9)
°C ≈ 37°C

Now, let's convert the average temperature of 98.2°F to Celsius:
°C = (98.2 - 32) * (5/9)
°C = 66.2 * (5/9)
°C ≈ 36.8°C

The difference between these averages in Celsius degrees is approximately:
37°C - 36.8°C = 0.2°C

So, the difference between the averages, expressed in Celsius degrees, is approximately 0.2°C.

the difference is 98.6 - 98.2 = 0.4°F

Since °C = 9/5 °F, that's 0.4*1.8 = 0.72°C