if a 30 newton force is required to accelerate a 2kg object at 10m/s2, over a level floor, what is the magnitude of the frictional force acting on the object

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To find the magnitude of the frictional force acting on the object, we can use Newton's second law of motion, which relates force, mass, and acceleration.

According to Newton's second law, the net force acting on an object is equal to the product of its mass and acceleration:

Fnet = m * a

Where:
Fnet is the net force acting on the object
m is the mass of the object
a is the acceleration of the object

In this case, the net force acting on the object is the difference between the applied force and the frictional force:

Fnet = Fa - Ff

Where:
Fa is the applied force
Ff is the frictional force

Given:
Fa = 30 Newtons
m = 2 kg
a = 10 m/s^2

Substituting these values into the equation for Newton's second law, we can solve for the frictional force:

30 N - Ff = 2 kg * 10 m/s^2

Simplifying the equation:

30 N - Ff = 20 kg m/s^2

Rearranging the equation to solve for Ff:

Ff = 30 N - 20 kg m/s^2

Calculating the value:

Ff = 30 N - 20 kg m/s^2
Ff = 30 N - 20 kg m/s^2
Ff = 10 N

Therefore, the magnitude of the frictional force acting on the object is 10 Newtons.

To find the magnitude of the frictional force acting on the object, we need to consider Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

Given:
Force (F) = 30 Newtons
Mass (m) = 2 kg
Acceleration (a) = 10 m/s^2

Using the formula F = m * a, we can calculate the net force acting on the object:
30 N = 2 kg * 10 m/s^2

Now, the net force acting on the object is 20 Newtons.

However, if the object is moving on a level floor without any external forces applied, then the frictional force must be equal in magnitude and opposite in direction to the applied force in order to maintain a constant velocity.

Therefore, the magnitude of the frictional force acting on the object is also 20 Newtons.

Fap-Fk = m*a

30-Fk = 2 * 10 = 20
Fk = 30-20 = 10 N. = Force of kinetic friction.