If x=(2/y^2)+2,what is the value of y in terms of x ?

please answer and explain

x = (2/y^2) + 2

Place the 2 from the right side to the left side.
x - 2 = 2 / y^2
Multiply both sides by y^2.
(x - 2) * y^2 = (2 / y^2) * y^2
(x - 2) * y^2 = 2
Divide 2 from the right side by x - 2 to isolate all terms with y.
y^2 = 2 / (x - 2)
Finally, get the squareroot.
y = sqrt( 2 / (x-2) )

Hope this helps :3

I like your answer and explain . step by step, now I understand how to do that.thank you, Jai

To find the value of y in terms of x, we can rearrange the equation:

x = (2/y^2) + 2

Subtract 2 from both sides:

x - 2 = 2/y^2

Next, invert both sides of the equation:

1/(x - 2) = y^2/2

To isolate y, we take the square root of both sides:

√(1/(x - 2)) = √(y^2/2)

Simplifying further:

± √(1/(x - 2)) = ±(y/√2)

Thus, in terms of x, y can be expressed as:

y = ± √(2/(x - 2))

Note that since we introduced a square root, y can have both positive and negative values.