an express train leaves new york at 3:00 pm and rreaches boston at 6:00 pm a slow train leaves boston at 1:30pm and arrives in new york at 6:00 pm. if both trains travel at constant speeds at what time do they meet
the sum of the distances traveled by each train is one trip.
Since distance = speed * time,
if x is the time traveled by the fast train,
x/3 + (x+3/2)/4.5 = 1
x = 6/5
So, in 1.2 hours, the trains meet. That is, at 4:12
A train leaves Orlando at 3:00 PM. A second train leaves the same city in the same direction at 5:00 PM. The second train travels 20 mph faster than the first. If the second train overtakes the first at 10:00 PM, what is the speed of each of the two trains?
To determine the time when the two trains meet, we need to calculate the time it takes for each train to reach the meeting point.
Let's start by finding the travel time of the express train. It departs from New York at 3:00 pm and arrives in Boston at 6:00 pm, which means it takes 3 hours to complete the journey.
Next, we'll calculate the travel time of the slow train. It departs from Boston at 1:30 pm and arrives in New York at 6:00 pm, meaning it also takes 3.5 hours to complete the journey.
Now, let's find the time of intersection by adding the departure time of the express train and the travel time of the slow train:
3:00 pm + 3.5 hours = 6:30 pm
Therefore, the express train and slow train will meet at 6:30 pm.