Simplify the following algebraic expression: b[b(b - 2) - 4] + 1
b [b(b-2) -4)] + 1
b [ b^2 -2b -4)] + 1
= b^3 -2b^2 -4b +1
thank you so much
To simplify the given algebraic expression, let's break it down step by step.
The expression is: b[b(b - 2) - 4] + 1
Step 1: Start by simplifying the expression within the inner parentheses.
Inside the first set of parentheses, we have (b - 2).
Next, we have b multiplied by (b - 2) within the second set of parentheses.
To multiply, distribute the b to each term within the parentheses:
b(b - 2) = b^2 - 2b
So, the expression becomes: b[b^2 - 2b - 4] + 1
Step 2: Continue simplifying by distributing the b to each term within the square brackets.
b[b^2 - 2b - 4] = b^3 - 2b^2 - 4b
So, the expression now simplifies to: b^3 - 2b^2 - 4b + 1
Therefore, the simplified form of the given algebraic expression is b^3 - 2b^2 - 4b + 1.