physics

An apartment has a living room whose dimensions are 2.5 m 4.8 m 5.9 m. Assume that the air in the room is composed of 79% nitrogen (N2) and 21% oxygen (O2). At a temperature of 27°C and a pressure of 1.01 105 Pa, what is the mass (in grams) of the air?

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asked by mike
  1. PV = nRT

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  2. volume = 2.5 x 4 x 5 = 50
    temperature = 22+273.15 = 295.15 k
    pressure = 1.01x 10^5 pa
    79% of N2 = 0.79
    21% of O2 = 0.21

    pv = nrt
    1.01 x 10^5 x 50 = n x 8.31 x 295.15
    n= 2059

    n = mass / mass over mole
    mass= 2059 x (0.79 x 14*2+0.21 *32)
    mass = 5.9*10^4

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    posted by jessica
  3. oh just change the temperature and the pressure in my equation. I got the wrong question but overall method is the same. Good luck!

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    posted by jessica

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