Glucose can be classified as an aldohexose. Name the following monosaccharide to indicate its carbonyl group and the number of carbon atoms.


HO-CH2-C(=o)-C(H2O)-C(H2O)-CH2-OH

The given monosaccharide can be classified as an aldopentose.

The given monosaccharide can be named as D-glucose, indicating that it is the D-isomer of glucose. The carbonyl group, which is an aldehyde group (-CHO), is attached to the first carbon atom. Therefore, the carbonyl group is located at C(=O)-C(1)-C(H2O)-C(H2O)-CH2-OH. Since glucose has six carbon atoms, it is classified as an aldohexose.

To name the given monosaccharide and indicate its carbonyl group and the number of carbon atoms, you need to analyze the structure.

The structure you provided can be broken down as follows:

HO-CH2-C(=O)-C(H2O)-C(H2O)-CH2-OH

Here's a step-by-step breakdown:

1. Identify the carbonyl group: In the given structure, there is a carbonyl group denoted by "=O". This means that the carbon atom attached to the oxygen is the carbonyl carbon.

2. Count the number of carbon atoms: In the given structure, there are six carbon atoms present. These can be counted from left to right:

HO-CH2-C(=O)-C(H2O)-C(H2O)-CH2-OH
1 2 3 4 5 6

3. Determine the type of monosaccharide: Based on the number of carbon atoms and the presence of the carbonyl group (aldose = carbonyl group at the end of the carbon chain), this monosaccharide is an aldohexose.

Putting it all together, the name of the monosaccharide with the structure HO-CH2-C(=O)-C(H2O)-C(H2O)-CH2-OH can be classified as an aldohexose with six carbon atoms.

Please note that without additional context or specific information, it is difficult to provide a specific name for this monosaccharide.