Algebra 2

What are the solutions of the quadratic equation?
2x^2 – 16x + 32 = 0

How do I solve this, I'm kinda new to quadratics and there confusing >.>

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  1. they're, not there.

    first, factor out the 2 so you have smaller numbers to work with

    2(x^2-8x+16) = 0

    Now you want two numbers which add to -8 and multiply to +16

    -4 and -4 fit the bill, so
    2(x-4)(x-4) = 0
    Now the answer is clear. x=4 is a double root.

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