A school has 6th, 7th and 8th period Social Studies classes. One student from each class will be chosen to represent the school in an essay contest. The 6th period finalists are Mike, Sara, Luis and Ed. The 7th period finalists are Ben, Eric, and Sandy. The 8th period finalista are Hilda, Liz and Rob. How many different ways can the students be chosen?

periods

│6│7│8│
no. of students for each of those periods:
4*3*3

so the number of ways is 36

To find the total number of ways the students can be chosen, we multiply the number of choices for each period:

Number of choices for 6th period: 4 (Mike, Sara, Luis, Ed)
Number of choices for 7th period: 3 (Ben, Eric, Sandy)
Number of choices for 8th period: 3 (Hilda, Liz, Rob)

Total number of ways: 4 x 3 x 3 = 36

Therefore, there are 36 different ways the students can be chosen to represent the school in the essay contest.

To find the total number of different ways the students can be chosen for the essay contest, you need to multiply the number of choices for each period.

In this case, the number of choices for each period is as follows:

For the 6th period, there are 4 finalists (Mike, Sara, Luis, and Ed).
For the 7th period, there are 3 finalists (Ben, Eric, and Sandy).
For the 8th period, there are 3 finalists (Hilda, Liz, and Rob).

To find the total number of different ways the students can be chosen, multiply these numbers together:

4 (choices for 6th period) x 3 (choices for 7th period) x 3 (choices for 8th period) = 36.

Therefore, there are 36 different ways the students can be chosen for the essay contest.