Determine the mass of copper(ii)trioxonitrate(v) that will be formed,when 15g of copper is added to excess diluted trioxonitrate(v) acid. (cu=63.5, N=14, O=16)
I will NEVER buy into trioxonitrate(v) for HNO3.
1. Write and balance the equation.
2. Convert g Cu to mols. mol = g/molar mass.
3. Using the coefficients in the balanced equation, convert mols Cu to mol Cu(NO3)2
4. Now convert mols Cu(NO3)2 to grams. g = mols x molar mass
Pls explain further
PLS ANSWER DE QUESTION PLS
1860g
answer
pls John can u explain more futher I was given this as an assignment
Please explain further
Isn't this question under stoichimetry ii
please I need your help
To determine the mass of copper(II) trioxonitrate(V) that will be formed when 15g of copper is added to excess diluted trioxonitrate(V) acid, we need to follow these steps:
Step 1: Write the balanced chemical equation for the reaction between copper and trioxonitrate(V) acid.
Cu + HNO₃ ⟶ Cu(NO₃)₂ + H₂O + NO₂
Step 2: Calculate the molar mass of copper (Cu).
The molar mass of copper (Cu) is 63.5 g/mol.
Step 3: Convert the mass of copper to moles.
We have 15g of copper. To convert it to moles, we use the formula:
moles = mass / molar mass
moles of copper (Cu) = 15g / 63.5 g/mol = 0.236 moles
Step 4: Use the balanced equation to determine the mole ratio between copper and copper(II) trioxonitrate(V) (Cu(NO₃)₂).
From the balanced equation:
1 mole of copper (Cu) reacts to form 1 mole of copper(II) trioxonitrate(V) (Cu(NO₃)₂)
Therefore, the moles of copper(II) trioxonitrate(V) formed will also be 0.236 moles.
Step 5: Calculate the molar mass of copper(II) trioxonitrate(V) (Cu(NO₃)₂).
The molar mass of copper(II) trioxonitrate(V) (Cu(NO₃)₂) can be calculated as:
Molar mass = (Atomic mass of copper + 2*(Atomic mass of nitrogen) + 6*(Atomic mass of oxygen))
Molar mass = (63.5g/mol + 2*(14g/mol) + 6*(16g/mol)) = 191.5 g/mol
Step 6: Convert moles of copper(II) trioxonitrate(V) to mass.
To convert moles to mass, we use the formula:
mass = moles * molar mass
mass of copper(II) trioxonitrate(V) = 0.236 moles * 191.5 g/mol = 45.214 g
Therefore, the mass of copper(II) trioxonitrate(V) formed will be approximately 45.214 grams when 15g of copper is added to excess diluted trioxonitrate(V) acid.