Four hoses are filling a pool. The first hose alone would fill the pool in 4 hours while the second hose takes 6 hours. The third hose and the fourth hose each take 8 hours to fill the pool. How long would it take to fill the pool if all 4hoses are turned on?

1.5 hours

ITS 1:30 NOOBS IMAGINE

1/x = 1/4 + 1/6 + 1/8 + 1/8

x = 3/2

Tea

1.5 bruhhh why

If the third and fourth hose sprouted leaks causing them to excrete half of their amount of water (1/8 divided by 2 = 1/16) then it would take about two hours!

To find out how long it would take to fill the pool when all four hoses are turned on, we can calculate the combined rate of all the hoses. The rate at which each hose fills the pool is given by the inverse of the time it takes for each hose to fill the pool.

First, let's calculate the rates of each hose:
- The first hose fills the pool in 4 hours, so its rate is 1/4 of the pool per hour (1 pool/4 hours = 1/4 pool/hour).
- The second hose fills the pool in 6 hours, so its rate is 1/6 of the pool per hour (1 pool/6 hours = 1/6 pool/hour).
- The third hose fills the pool in 8 hours, so its rate is 1/8 of the pool per hour (1 pool/8 hours = 1/8 pool/hour).
- The fourth hose fills the pool in 8 hours as well, so its rate is also 1/8 of the pool per hour.

To find the combined rate, we sum up the individual rates of all the hoses:
1/4 + 1/6 + 1/8 + 1/8 = (3/12) + (2/12) + (1/8) + (1/8) = 7/24 pool/hour.

Therefore, when all four hoses are turned on, the combined rate is 7/24 of the pool per hour. To find how long it would take to fill the pool, we can take the reciprocal of the combined rate:

(24/7) hours/pool ≈ 3.43 hours.

So, it would take approximately 3.43 hours to fill the pool if all four hoses are turned on.