imageshack(.)(us)/photo/my-images/834/j6wv.jpg/
imageshack(.)(us)/photo/my-images/17/6n4x.jpg/
please PLEASE IM BEGGING YOU MY TEACHER WILL BE GIVING ME 79 IF I DIDN'T GET THIS .. OR ELSE LOWER THAN THAT. PLEASE
TRIANGLE SIMILARITIES RATIOS AND PROPORTIONS - BARBIE LEE, Wednesday, November 20, 2013 at 8:06am
just delete the parethesis please
TRIANGLE SIMILARITIES RATIOS AND PROPORTIONS - Reiny, Wednesday, November 20, 2013 at 10:52am
The key to this question is to realize that all the right -angled triangles are similar, and have the
ratio of 3:4:5 in the length of their sides.
Mark the two angles in triangle BCD with o and x
( you should be able to see that since XD | BC , so you can mark XDC as o and DCX as x
continue through the other triangles...)
Triangle XDC is similar to triangle DCB
XD:XC:DC = DC:DB:CB = 4:3:5
4p:3p:4
4p/4 = 4/5
4p = 16/5 ----> XD = 16/5
3p/4 = 3/5
3p=12/5 ----> XC = 12/5
and of course ---> CD = 4
now you have all the sides of triangle XDC
Did you notice that
3:4:5 = (5/4)(12/5 : 16/5 : 4) ??
continue in this fashion until you have all sides needed.
TRIANGLE SIMILARITIES RATIOS AND PROPORTIONS - Anonymous, Wednesday, November 20, 2013 at 4:26pm
yes sir ive got that already. i don't know what to do next. please help
For http://imageshack.us/photo/my-images/834/j6wv.jpg/
all the triangles are 3:4:5 So, since
DB=3 and BC=5,
a=4
So, ∆DBC ~ ∆XCD, so
b/3 = 4/5
c/4 = 4/5
b = 3(4/5) = 12/5
c = 4(4/5) = 16/5
∆MDX ~ ∆DBC, but has a hypotenuse of c=16/5. Since it's another 3:4:5 triangle,
d/c = 3/5
g/c = 4/5
d = 3(16/25) = 48/25
g = 4(16/25) = 64/25
Now continue with the other triangles. Just watch the details. They are all 3:4:5 triangles scaled by some amount.
It seems like you are working on a problem related to triangle similarities, ratios, and proportions. The key to this question is to realize that all the right-angled triangles in the given image are similar and have a ratio of 3:4:5 in the length of their sides.
To solve this problem, you can start by marking the two angles in triangle BCD with "o" and "x". Since XD is parallel to BC, you can mark XDC as "o" and DCX as "x".
Now, observe that triangle XDC is similar to triangle DCB. Using the given ratio, we can set up the following proportion:
XD : XC : DC = DC : DB : CB = 4 : 3 : 5
Solve for the lengths of XD and XC.
To find XD, we have:
4p : 3p : 4 = 4/5
Simplify and solve for XD:
4p = 16/5
Similarly, for XC, we have:
3p : 4 = 3/5
Simplify and solve for XC:
3p = 12/5
We know that CD is 4 units long.
Now, we have the lengths of XD, XC, and CD.
Do you notice that 3:4:5 can be written as (5/4) * (12/5 : 16/5 : 4)?
Following this pattern, you can continue to find all the sides needed using proportions and the given ratio.
I hope this helps! Keep working through the problem step by step, and remember to use the given ratios to find the lengths of the sides of similar triangles.