Balance the equation:
Note: If a chemical species coefficient is "1" then "1" needs to be entered in the field before that species.
___MnO4(–) + __H(+) + ___Fe2 + __Mn(2+) + ___H2O + ____Fe(3+)
i got 1,8,1,1,4,1 but the second coeffient(one) and the last coeffient(one) are incorrect. im not sure what goes for ____Fe(2+) and ___Fe(3+)
thats not the ansr, need a check
The error you are making is that you are not making the loss of electrons equal to the gain of electrons. Mn goes from +7 on the left to +2 on the right, a gain of 5 electrons. Fe goes from +2 on the left to +3 on the right, a loss of 1 electron. To make the gain and loss of electrons equal, Mn must be multiplied by 1 and Fe by 5.
Therefore, 1 MnO4^-, 1 Mn, 5Fe^+2, and 5Fe^+3 are the basic numbers. I think your other numbers are ok but check them, too, after putting in those four that must be correct to start the balancing.
To balance the equation, we need to make sure that the number of each type of atom is the same on both sides of the equation.
Let's go through this step by step.
1. Start by counting the number of atoms on each side:
On the left side:
- Mn: 1
- O: 4
- H: 1
- Fe: 2
On the right side:
- Mn: 1
- O: 2
- H: 2
- Fe: 1
2. Identify the atoms that are not balanced:
In this case, Mn and Fe are not balanced.
3. Balance the metals:
Since there is only one Mn on each side of the equation, they are already balanced.
To balance the Fe, we need to have the same number of Fe atoms on both sides. We currently have 2 Fe atoms on the left side and 1 Fe atom on the right side. To equalize them, we can put a coefficient of "2" in front of the Fe(3+) on the right side:
MnO4(–) + __H(+) + ___Fe2 + __Mn(2+) + ___H2O + 2 Fe(3+)
4. Balance oxygen (O) atoms:
On the left side, we have 4 O atoms from the permanganate ion (MnO4(-)). On the right side, we have 2 O atoms from the water (H2O) and 3 O atoms from the ferric ion (Fe(3+)). This means we have 5 O atoms in total on the right side.
To equalize the O atoms, we can add 3 water molecules (H2O) on the left side:
MnO4(–) + __H(+) + ___Fe2 + __Mn(2+) + 3 H2O + 2 Fe(3+)
5. Balance hydrogen (H) atoms:
On the left side, we have 1 H atom from the hydrogen ions (H(+)). On the right side, we have 6 H atoms from the water molecules (3 H2O). This means we have a total of 7 H atoms on the right side.
To equalize the H atoms, we need to add 6 hydrogen ions (H(+)) on the left side:
MnO4(–) + 6 H(+) + ___Fe2 + __Mn(2+) + 3 H2O + 2 Fe(3+)
Now the equation is balanced, with the same number of atoms on both sides:
MnO4(–) + 6 H(+) + ___Fe2 + __Mn(2+) + 3 H2O + 2 Fe(3+)
Please note that there may be other valid ways to balance this equation, but this is one possible solution.