How many moles of CaCl2 are produced when this reaction is started with 4.70 grams of chlorine gas?
What reaction?
Ca+Cl2->CaCl2
Ca + Cl2 -> CaCl2
mols Cl2 = grams/molar mass = ?
Then use the coefficients in the balanced equation to convert mols Cl2 to mols CaCl2.
To determine the number of moles of CaCl2 produced, you first need to identify and balance the chemical equation for the reaction in question. Once you have the balanced equation, you can use stoichiometry to calculate the moles of CaCl2.
Assuming the reaction you are referring to is the combination of chlorine gas (Cl2) with calcium (Ca) to form calcium chloride (CaCl2), the balanced chemical equation is:
Ca + Cl2 -> CaCl2
From the balanced equation, we can see that 1 mole of calcium reacts with 1 mole of chlorine gas to produce 1 mole of calcium chloride.
To calculate the number of moles of CaCl2 produced, you need to convert the given mass of chlorine gas (in grams) to moles. The molar mass of chlorine gas (Cl2) is approximately 70.90 g/mol.
First, divide the given mass of chlorine gas (4.70 grams) by the molar mass of chlorine gas (70.90 g/mol):
4.70 g Cl2 / 70.90 g/mol = 0.0661 mol Cl2
Thus, starting with 4.70 grams of chlorine gas, you have 0.0661 moles of chlorine gas.
Since the balanced equation shows a 1:1 mole ratio between chlorine gas and calcium chloride, the number of moles of CaCl2 produced is also 0.0661 moles.
Therefore, when the reaction is started with 4.70 grams of chlorine gas, 0.0661 moles of CaCl2 are produced.