Using the linear equation y = -3x + 5, complete the table of values (T-Chart) and choose the correct graph.
X = -2 Y = _
X = -1 Y = _
X = 0 Y = _
X = 1 Y = _
X = 2 Y = _
To complete the table of values using the linear equation y = -3x + 5, we substitute each given value of x into the equation and calculate the corresponding value of y.
Plugging in x = -2:
y = -3(-2) + 5
y = 6 + 5
y = 11
Thus, when x = -2, y = 11.
Plugging in x = -1:
y = -3(-1) + 5
y = 3 + 5
y = 8
When x = -1, y = 8.
For x = 0:
y = -3(0) + 5
y = 0 + 5
y = 5
So, when x = 0, y = 5.
For x = 1:
y = -3(1) + 5
y = -3 + 5
y = 2
Therefore, when x = 1, y = 2.
Lastly, for x = 2:
y = -3(2) + 5
y = -6 + 5
y = -1
Hence, when x = 2, y = -1.
The completed table of values is as follows:
X | Y
------
-2 | 11
-1 | 8
0 | 5
1 | 2
2 | -1
By plotting the points (x, y) from the table of values on a graph, we can determine the correct graph for the linear equation y = -3x + 5.
To complete the table of values, we can substitute the given values of x into the equation y = -3x + 5:
X = -2: y = -3(-2) + 5 = 6 + 5 = 11. So, when x = -2, y = 11.
X = -1: y = -3(-1) + 5 = 3 + 5 = 8. So, when x = -1, y = 8.
X = 0: y = -3(0) + 5 = 0 + 5 = 5. So, when x = 0, y = 5.
X = 1: y = -3(1) + 5 = -3 + 5 = 2. So, when x = 1, y = 2.
X = 2: y = -3(2) + 5 = -6 + 5 = -1. So, when x = 2, y = -1.
The completed table of values is as follows:
X | Y
-2 | 11
-1 | 8
0 | 5
1 | 2
2 | -1
From the values in the table, we can plot the points (-2, 11), (-1, 8), (0, 5), (1, 2), and (2, -1) on a graph. By connecting these points with a straight line, we would get the graph of the linear equation y = -3x + 5.