A 2.2 kg otter starts from rest at the top of a muddy incline 93.9 cm long and slides down to the bottom in 0.60 s.
What net external force acts on the otter along the incline?
Does anyone know how to do this?
gravity acts on the otter, and friction acts on the otter.
But the question requires a number answer. What should I do for that?
A 2.4 kg otter starts from rest at the top of a
muddy incline 94.9 cm long and slides down
to the bottom in 0.60 s.
What net external force acts on the otter
along the incline?
Answer in units of N.
It's 11.77N
Yes, I can help you with that!
To find the net external force acting on the otter along the incline, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration: Fnet = m * a.
First, we need to calculate the acceleration of the otter. We can use the equation of motion for uniformly accelerated linear motion: s = ut + (1/2)at^2.
Given:
- Initial velocity (u) = 0 m/s (since the otter starts from rest)
- Distance traveled (s) = 93.9 cm = 0.939 m
- Time taken (t) = 0.60 s
Using the equation above, we can rearrange it to solve for acceleration (a):
a = 2(s - ut) / t^2
Substituting the given values into the equation, we get:
a = 2(0.939 m - 0 m) / (0.60 s)^2
a ≈ 5.234 m/s^2
Now, we can calculate the net external force using Newton's second law. Given:
- Mass of the otter (m) = 2.2 kg
- Acceleration (a) = 5.234 m/s^2
Using the formula Fnet = m * a, we have:
Fnet = 2.2 kg * 5.234 m/s^2
Fnet ≈ 11.5148 N
Therefore, the net external force acting on the otter along the incline is approximately 11.5148 Newtons.
s=at²/2
a=2s/t²=2•0.939/0.6²=5.22 m/s²
F=ma=2.2•5.22=11.484 N