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Rationalize the denominator. Assume that all expressions under radicals represent positive numbers. The square root of 3y^4 to the third root divided by the square root of 15x^4 to the third root. Here is what I have so far: I
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Algebra
69: 16x^2+8x3. I inserted this into the quadratic formula and got 8+/ the square root of (8^24(16)(3)/(2 times 16). This reduced to 8+/ the square root of (64+120)/32, which further reduced to 8+/the square root of
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Use the quadratic formula to solve the equation. Give exact answers: 2x^2 1 = 6x. The choices are: a) 3 + square root(7)/2, 3  square root(7)/2 b) 3 + square root(11)/2, 3  square root(11)/2 c) 3 + square root(7)/2, 3 
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asked by Kay on December 9, 2015 
Algebra
Express the following in simplest radical form. All variables represent positive real numbers. square root of 80a^2b divided by the square root of7a^3b^7 I got an answer of 4 square root of 5 divided by b^3 square root of 7a
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Algebra
I am supposed to "write each expression with a rational denominator" 1/thesqrootof 3. I follow the book's explanation, until it suggests dividing the sq. root of 3 by the square root of 3 times the square root of three. I do not
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Simplify: 3 squared divided by the square root of 80. Multiple choices: 1. square root of 80 divided by 3 to the negative 2nd power 2. 4 over 9 times the square root of 5 3. 5 over 4 times the square root of 5 4. 9 over 20 times
asked by anonymous on December 3, 2007 
physics
Suppose that the displacement of a particle is related to time according to the expression delta x = ct^3. What are the SI units of the proportionality constant c? My answer: delta x = ct^3 m = c s^3 (s: seconds) m/s^3= c The SI
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1.0 Four square root of seven open bracket two square root of three plus three square root of six minus square root of seven close bracket. 2.0 open bracket three square root of seven minus square root of two close bracket
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