How much heat is gained (in Joules) by the water (qwater) when a chemical reaction takes place in 100.0 mL aqueous solution and has a temperature increase of 13.26 °C? (Remember cwater = 4.180 J/°Cg)

heat=masswater*cwater*(13.26)

100ml of water is 100g of water

To calculate the heat gained by the water (qwater), we can use the formula:

qwater = m * cwater * ΔT

Where:
- qwater is the heat gained by the water in Joules
- m is the mass of the water in grams
- cwater is the specific heat capacity of water in J/°Cg
- ΔT is the temperature change of the water in °C

In this case, we have the volume of the aqueous solution (100.0 mL) and the specific heat capacity of water (4.180 J/°Cg), but we need to determine the mass of the water.

To find the mass of the water, we can use the density formula:

density = mass / volume

The density of water is approximately 1 g/mL. Therefore, the mass of the water is:

mass = volume * density

mass = 100.0 mL * 1 g/mL

mass = 100.0 g

Now we have all the values we need to calculate qwater:

qwater = 100.0 g * 4.180 J/°Cg * 13.26 °C

qwater = 55492.8 J

Therefore, the water gains approximately 55492.8 Joules of heat when the chemical reaction takes place in a 100.0 mL aqueous solution with a temperature increase of 13.26 °C.