What is the Molar Enthalpy of Neutralization (ÄHn) in kJ/mol if 5.00 moles of HCl(aq) (acid) neutralized 5.00 moles of NaOH(aq) (base) and released 2033 J of heat?

To find the molar enthalpy of neutralization (ÄHn) in kJ/mol, you need to convert the given value of heat released from J to kJ and then divide it by the number of moles of the limiting reactant (either the acid or the base).

Step 1: Convert Heat from J to kJ
The given value of heat released is 2033 J. To convert this to kJ, divide it by 1000 (1 kJ = 1000 J):
2033 J ÷ 1000 = 2.033 kJ

Step 2: Determine the Limiting Reactant
In this case, both the acid (HCl) and the base (NaOH) are present in equal amounts (5.00 moles). Therefore, the limiting reactant is either the acid or the base. Since the ÄHn is the same regardless of which reactant is the limiting reactant, you can choose either one for the calculation.

Step 3: Calculate ÄHn in kJ/mol
Divide the converted heat value (in kJ) by the number of moles of the limiting reactant:
ÄHn = 2.033 kJ ÷ 5.00 moles = 0.4066 kJ/mol

Therefore, the molar enthalpy of neutralization (ÄHn) is 0.4066 kJ/mol.