The following table shows a frequency distribution of patients with colon cancer treated at Community Hospital. Compute the proportion of patients in each category.
Community Hospital Ages of Patients with Colon Cancer Annual Statistics, 20XX
Age No. of Patients Proportion
≤ 30 3
31-40 12
41-50 18
51-60 60
61-70 65
71+ 48
This is healthcare statistics. Can someone help me with this and guide me in the right direction. I can't remember how to do it. Can you help me with 1st proportion answer and the formula used. Thank you very much.
Anyone out there, that can help me with this please?? I need to understand how to figure the problems out.
Proportion = # in category/total number
Thank you I did manage to figure it out yesterday. I totaled the # of patients which was 206 and divided the individual # of patients by the total for example 48/206=0.23
Thank you PsyDAG for your help.
Certainly! To find the proportion of patients in each category, you need to divide the number of patients in each category by the total number of patients.
In this case, the total number of patients is the sum of the patients in all categories. From the given table, we can see that the total number of patients is:
Total = 3 + 12 + 18 + 60 + 65 + 48 = 206
To find the proportion for the category "≤ 30", you divide the number of patients in that category (which is 3) by the total number of patients (which is 206).
Proportion of patients in the "≤ 30" category = 3 / 206 = 0.0146 (rounded to four decimal places)
So, the proportion of patients in the "≤ 30" category is approximately 0.0146.
The formula used to find the proportion is:
Proportion = Number of patients in a category / Total number of patients
You can repeat this process for the other categories to find their respective proportions.