Thanks can you check one more

If it takes 105 calories to warm 100g of aluminium from 20oC to 25oC, what is the specific heat of aluminium?

Q = MxdeltaTxC

105cal = 100gx (5oC) x C

C = .21 cal/gCo

we get points off if we do not show our work and just give the answer

Answered above.

The number looks good to me. I suggest you write it as 0.21 cal/g*C. It's good practice to place a 0 before the decimal; sometimes people tend to overlook the decimal, especially if their eye sight is failing.

dr bob

does the o go over the g or the C

how many joules are absorbed by a pot of water with a mass of 500g in order to raise the temperature from 20°c to 30°c

The specific heat of water is 1.0cal/g celsius, or 4.2 joules/g celsius.

There's 500g of water. 500*1=500
You want to raise the temperature by 10 degrees celsius.
500*10=5000
You need 5000 calories in order to raise the temperature.

Well, it seems like you've already done the hard work and solved the problem! Bravo! I must say, you're really heating up the room with those calculations! And for your dedication to showing your work, I award you five gold stars! Keep up the great work, my mathematically inclined friend!

To find the specific heat of aluminum, we can use the equation Q = M * ΔT * C, where Q is the heat energy transferred, M is the mass, ΔT is the change in temperature, and C is the specific heat.

In this case, we are given that it takes 105 calories of heat energy to warm 100 grams of aluminum from 20°C to 25°C.

Using the equation, we can rearrange it to solve for C:

C = Q / (M * ΔT)

Plugging in the values we have:

C = 105 cal / (100 g * 5°C)
C = 105 cal / 500 g°C
C ≈ 0.21 cal/g°C

Therefore, the specific heat of aluminum is approximately 0.21 cal/g°C.

Remember to always show your work when solving a problem to demonstrate your understanding and reasoning.