Question

If m#= m/m^2-m ,what is the value of 6#-[(-5)#]?

a. 1/30
b. 1/20
c. 1/4
d. 11/30
e. 9/20

please answer and explain

Answer 1

Assuming you mean m# = m/(m^2-m)

then m# = 1/(m-1)

6#-[(-5)#]
= 6#-[-1/6]
= 6#+(1/6)
= 1/5 + 1/6
= 11/30