A ball, of mass 0.3Kg, is held on the inside of a smooth hemispherical bowl at a height 0.09 m above the base. It is then released. Assuming there is no friction, the acceleration due to gravity, g, is 10 m/s2 and the potential energy is zero at the base of the bowl - What is the maximum value of speed that the ball reaches?
mgh = mv²/2
v=sqrt(2gh)