Physics

A 14.9-kg object hangs in equilibrium at the end of a rope (taken as massless) while a wind pushes the object with a 67.7-N horizontal force. Find the tension in the rope and the rope\'s angle from the vertical. The acceleration due to gravity is 9.81 m/s2.

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asked by James
  1. x: F=Tsinα
    y: mg=Tcosα
    F/mg=Tsinα/ Tcosα
    tanα =F/mg=67.7/14.9•9.8 = 0.46
    α =arctan0.46= 24.9⁰
    T=F/sinα=67.7/sin24.9=67.7/0.42=161 N

    posted by Elena

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