Scott, Mike, and Holly shared an order of French fries. Scott ate x fries. Mike ate one more than twice the amount of fries that Scott ate. Holly ate 5 fewer fries than Scott did. If there were 6 fries left, how many fries were in the order?
a. x-5
b. x
c. 2x+`1
d. 4x-4
e. 4x+2
please answer and explain
Scott ate X Fries
Mike ate (2x+1) Fries.
Holly ate (x-5) Fries.
Total fries ordered = Fries ate + 6:
ORDER = X + (2x+1) + (x-5) + 6 = 4x + 2.
Let's break down the information given:
1. Scott ate x fries.
2. Mike ate one more than twice the amount of fries that Scott ate, which means Mike ate (2x + 1) fries.
3. Holly ate 5 fewer fries than Scott did, which means Holly ate (x - 5) fries.
4. There were 6 fries left.
To find the total number of fries in the order, we can add up the number of fries each person ate and the number of fries left over:
Scott's fries + Mike's fries + Holly's fries + Fries left over = Total fries in the order.
Substituting the values we have:
x + (2x + 1) + (x - 5) + 6 = Total fries in the order.
Simplifying the equation:
4x + 2 = Total fries in the order.
Therefore, the correct answer is e. 4x + 2, which represents the total number of fries in the order.
To find the total number of fries in the order, we need to add up the number of fries each person ate and the number of fries left at the end.
Let's analyze the information given in the problem:
1. Scott ate x fries.
2. Mike ate one more than twice the amount of fries Scott ate. So, Mike ate (2x + 1) fries.
3. Holly ate 5 fewer fries than Scott did. So, Holly ate (x - 5) fries.
4. There were 6 fries left.
Now, we need to add up the number of fries each person ate:
Scott: x fries
Mike: (2x + 1) fries
Holly: (x - 5) fries
Adding these three amounts together will give us the total number of fries:
Total fries = x + (2x + 1) + (x - 5)
Simplifying the expression:
Total fries = x + 2x + 1 + x - 5
Total fries = 4x - 4
So, the total number of fries in the order is 4x - 4.
Therefore, the correct answer is option d) 4x - 4.